d | ρ | Label | ID | ||
---|---|---|---|---|---|
C53 | 125 | C5^3 | 125,5 |
extension | φ:Q→Aut N | d | ρ | Label | ID |
---|---|---|---|---|---|
C52⋊C5 = He5 | φ: C5/C1 → C5 ⊆ Aut C52 | 25 | 5 | C5^2:C5 | 125,3 |
extension | φ:Q→Aut N | d | ρ | Label | ID |
---|---|---|---|---|---|
C52.C5 = 5- 1+2 | φ: C5/C1 → C5 ⊆ Aut C52 | 25 | 5 | C5^2.C5 | 125,4 |